From 03403ba333c3c0b7e6b0ae6895a5481edbfb5d08 Mon Sep 17 00:00:00 2001
From: huminmin <mac@MacBook-Pro.local>
Date: 星期四, 02 七月 2026 14:40:39 +0800
Subject: [PATCH] 采购台账,可用数量为实际入库数量。存在采购质检部分合格入库情况。只有可用数量大于0进行采购退货操作

---
 src/main/resources/mapper/sales/SalesLedgerProductMapper.xml |   11 +++++------
 1 files changed, 5 insertions(+), 6 deletions(-)

diff --git a/src/main/resources/mapper/sales/SalesLedgerProductMapper.xml b/src/main/resources/mapper/sales/SalesLedgerProductMapper.xml
index b39b720..2d3be6a 100644
--- a/src/main/resources/mapper/sales/SalesLedgerProductMapper.xml
+++ b/src/main/resources/mapper/sales/SalesLedgerProductMapper.xml
@@ -35,6 +35,7 @@
         END as has_sufficient_stock,
         (IFNULL(T1.quantity, 0) - IFNULL(t3.shipped_quantity, 0) - IFNULL(t5.pending_approval_quantity, 0)) as no_quantity,
         IFNULL(t6.return_quantity, 0) as return_quantity,
+        IFNULL(t4.approved_stock_in_num, 0) as approved_stock_in_num,
         IFNULL(t5.pending_approval_quantity, 0) as pending_approval_quantity,
         CASE
          WHEN IFNULL(t3.shipped_quantity, 0) = 0 AND IFNULL(t5.pending_approval_quantity, 0) = 0 THEN '寰呭彂璐�'
@@ -115,12 +116,10 @@
         GROUP BY si.sales_ledger_product_id
         ) t5 ON t5.sales_ledger_product_id = T1.id
         LEFT JOIN (
-        SELECT si.sales_ledger_product_id, IFNULL(SUM(rsp.num), 0) AS return_quantity
-        FROM return_management rm
-        INNER JOIN return_sale_product rsp ON rm.id = rsp.return_management_id
-        INNER JOIN shipping_info si ON rm.shipping_id = si.id
-        WHERE rm.status = 1
-        GROUP BY si.sales_ledger_product_id
+        SELECT prop.sales_ledger_product_id, IFNULL(SUM(prop.return_quantity), 0) AS return_quantity
+        FROM purchase_return_order_products prop
+        INNER JOIN purchase_return_orders pro ON prop.purchase_return_order_id = pro.id
+        GROUP BY prop.sales_ledger_product_id
         ) t6 ON t6.sales_ledger_product_id = T1.id
         left join product_model pm ON T1.product_model_id = pm.id
         left join product p ON pm.product_id = p.id

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